题目内容
(请给出正确答案)
[不定项选择题]
某钢尺的尺长方程式为:L=30-0.003+1.25×10-5×30×(t-20℃),若用其在4℃的温度下丈量了60m,则其温度改正数和实际长度分别为()。
A.-0.012m;59.988m
B.+0.012m;60.012m
C.-0.012m;59.982m
D.+0.012m;59.982m
答案
暂无答案
A.-0.012m;59.988m
B.+0.012m;60.012m
C.-0.012m;59.982m
D.+0.012m;59.982m
第1题
A.-0.121
B.0.0424
C.0.0121
D.0
第3题
A.-0.0172
B.0.0172
C.-0.0118
D.0.0118